2022/2023 WAEC Chemistry Practical Questions And Answers (Complete Result)

 WAEC Chemistry Practical Questions and Answers2022/ 2023 ( Complete Result) 

 

 WAEC Chemistry Practical 2022. Multitudinous WAEC contenders find it delicate to answer the WAEC Practical Chemistry Alternative A and B correctly due to not understanding the questions. I will show you the swish way to answer the 2022 WAEC Chemistry Practical questions and make a good grade in your Chemistry examination. 

 

 

 

 

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 It's material you understand the WAEC Chemistry Practical timber scheme before trying any questions so as to present your answers in such a way that it will look attractive to the examiner to earn you big marks. 

 

 

 

 

 

 

 

 Bear in mind that every single procedure is awarded marks. So, ensure you do not skip any step while reporting and presenting your practical results. 

 

 

 

 

 

 The Chemistry Practical question paper will correspond of two sections and general Chemistry questions videlicet 

 

 

 

 Quantitative Analysis 

 

 Qualitative Analysis 

 

 These involve titration and test of ions. You will be anticipated to carry out an trial and report your conclusion and observation. What you will see will not be far from the WAEC Chemistry Specimen given to your academe. 

 

 

 

 Note Your titration endpoint will be given to you by your Chemistry teacher. It is not the same for every academe but within a range. 

 

 

 

 

 

 

 

 

 

 Do not use the endpoint also. It may vary from your center endpoint but you can follow the calculation procedures. 

 

 

 

 See 

 

 

 

 WAEC Medicines Practical 

 

 Check WAEC Timetable to know the coming test 

 

 WAEC Biology Practical 

 

 WAEC Economics Answers 

 

 WAEC Practical Chemistry Questions and Answers ( Exhibition) 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 3ai) The value will increase 

 

 

 

 (3aii) The do as a result of the drop in the attention of base due to the added volume of water 

 

 

 

 (3bi) There will be no visible response because bobby is lower than Zinc in the electrochemical series 

 

 

 

 

 

 (3bii) It absorb water and come sticky because it's hygroscopic (3biii) The result turns pink 

 

 

 

 

 

 

 

 

 

 

 

 

 

 (3c) When NaOH is added to the result of zn ³, a white precipitate is formed which subsequently dissolve in spare NaOH due to the conformation of zinc 

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 All your burette readings (initials and final) as well as the size of your pipette must be recorded but no account trial procedure is demanded. all calculations must be done in your answer brochure. 

 

 

 

 

 

 

 

 1. A is a result of potassium tetraoxomanganate (VII). B is a result of iron (II) Chloride containing4.80 g of the tar in 250cm3 of result. (a) Put A into the burette. Pipette20.0 cm3 or25.0 of B into a conical teacup, add20.0 cm3 of H2SO4 (aq) and titrate withA. repeat the titration to gain coherent titire values. Tabulate your results and calculate the average volume of A used. The equation of the response is MnO – 4 (aq) 5Fe2 (aq) 8H (aq)> Mn2 (aq) 5Fe3 (aq) 4H2O (I) 

 

 

 

 

 

 

 

 

 

 (b) From your results and the information handed, calculate the (i) attention of B in moldm-3; (ii) Attention of A in moldm-3 (iii) number of intelligencers of Fe2 in the volume of B pipetted (FeCI2 = 127 gmol-1) Credit will be given for strict adherence to the illustrations for obediences precisely and for accurate consequences. all tests, obediences and consequences must be fluently entered in the brochure in essay at the time they are made. 

 

 

 

 2. C and D are inorganic hearties. Carry out the following exercises on them. Record your obediences and identify any gas (es) evolved. State the conclusions and draw fromt the result of each test. (a) Put all of C in a test tube and add about 5cm3 of distilled water. Shake fully and test the performing result with litmus paper. Divide the result into three portions. (i) To the first portion, add NaOH (aq) in drops, also in excess. (ii) To the alternate portion, add NH3 (aq) in drops, also in excess. (iii) To the third portion, add AgNO3 (aq) followed by HCI (aq) (b) (i) Put all of D in a test tube and add about 5cm3 of distilled water. Shake fully and feel the test tube. (ii) To about 2cm3 of the result, add HCI (aq). 

 

 

 

 

 

 3. State the obediences that would be made when each of the following responses are carried out in the laboratory (a) Addition of 2cm3 of bench H2SO4 (aq) to 2cm3 of barrium chloride result; (b) Addition of 2cm3 of dilute hydrochloric acid to 1 g of powered iron (II) sulphide (FeS); (c) Addition of 2cm3 of dilute hydrochloric acid to 1 g of iron forms and allowed to stand for ultimately. 

 

 

 

 ANSWERS 

 

 

 

 1. Equation of the response MnO – 4 (aq) 5Fe2 (aq) 8H (aq)> Mn2 (aq) 5Fe3 (aq) 4H2O (I) 

 

 

 The questions above are strictly for practice, not henceforth’s Chemistry exhibition. 

 

 

 

 Farther answers and the 2022 WAEC Chemistry questions and answers loading … 

 

 

 

 Note The 2022 WAEC Chemistry Practical answers will be posted also during the WAEC Practical Chemistry test. Keep checking and reloading this runner to know when the answers are posted. Do not forget to reload this runner in order to see the answers. 

 

 

 

 Moment’s Practical Chemistry Answers 

 

 

 

 (2020 Answers) 

 

 

 

 3ai) 

 

 oxygen 

 

 

 

 

 

 (3c) 

 

 

 

 It turns blue acid test paper red. 

 

 

 

 3d 

 

 Pure bull (II) sulfate is white. It's also known as anhydrous bull (II) sulfate because it has no water in it. When water is present in a sample of bull (II) sulfate it turns blue. … This colour change can be used to descry the presence of water (or water vapour). 

 

 

 

 

 

 3c (i) 

 

 When exposed to light, tableware chloride decomposes into gray metallic tableware and chlorine. The light perceptivity of the tableware chloride and other tableware halides, analogous as tableware bromide and tableware iodide, forms the base of the photographic process. 

 

 

 

 

 

 3bi () 

 

 

 

 Phenolphtalein is chosen because it changes color in a pH range between8.3 – 10. It will appear pink in introductory results and clear in acidic results. 

 

 

 

 

 

 3c (i) 

 

 When exposed to light, tableware chloride decomposes into gray metallic tableware and chlorine. The light perceptivity of the tableware chloride and other tableware halides, analogous as tableware bromide and tableware iodide, forms the base of the photographic process. 

 

 

 

 3cii 

 

 The ammonia combines with tableware ions to produce a complex ion called the diamminesilver (I) ion, (Ag (NH3) 2). This is a reversible response, but the complex is truly stable, and the position of equilibrium lies well to the right. 

 

 

 

 3d 

 

 Pure bull (II) sulfate is white. It's also known as anhydrous bull (II) sulfate because it has no water in it. When water is present in a sample of bull (II) sulfate it turns blue. … This colour change can be used to descry the presence of water (or water vapour). 

 

 

 

 Remember What I told you Use your academe endpoints to avoid being a scapegoat. Your teacher will be the one to report, any endpoint reported by him will be taken as an accurate result. Shine your eyes while copying. Goodluck 

 

 

 

 

 

 

 

 (1a) 

 

 Burette reading (cm) ³| 1st reading| 2na Reading| 3rd reading| 

 

 Final|15.25|30.53|45.79| 

 

 Original|0.00|15.25|30.53| 

 

 Volume of acids used|15.25|15.28|15.26 

 

 

 

 Average volume of acid used = 15.2515.26/ 2 

 

 = 15.255 cm ³ 

 

 = 15.26 cm ³ 

 

 Or = 15.27 cm ³ 

 

 

 

 (1b) 

 

 Given; mass con of A = 5g/ 500 cm ³ = 5g/0.5 dn ³ 

 

 CA = 10g/ dm ³ 

 

 A is HNO3 

 

 Therefore molar mass = 1 14 (16 * 3) = 15 48 = 63g/ asset ¹ 

 

 

 

 Molarity of A = gram con/ molar mass 

 

 CA = 10/63 = 0.1587 asset/ dm3 

 

 

 

 (1bii) 

 

 Using CAVA/ CBVB = Na/ NB 

 

 With replying equation; HNO ³ NaOH — NaNO3 H2O 

 

 nA = 1 nB = 1 

 

0.1587 *15.26/ CB *25.00 = 1/1 

 

 25CB = 0.1587 *15.26 

 

 CB = 0.1587 *15.26/ 25 

 

 CB = 0.09687 asset/ dm ³ 

( 1biii) 

 

 B is NaOH 

 

 Molar mass 

 

 23 16 1 = 40g/ asset 

 

 Conc of B in g/ dm ³ = molarity * molar mass 

 

 = 0.09687 * 40 

 

 = 3.8748 g/ dm ³ 

 

 

 

 (1biv) 

 

 No of intelligencers present in 250 cm ³ of NaOH is = molar conc * volume 

 

 = 0.09687 *250/1000 

 

 = 0.0242 intelligencers 

 

 Operative rate of NaOH and NaNO3 is 1; 1 

 

 No; of operative of NaNO3 which replied is0.0242 

 

 Mass of NaNO3 formed = molar mass * no; of intelligencers 

 

 = 85 *0.0242 

 

 = 2.05 grams 

 

 ===================================== 

 

 

 

 (2a) 

 

 TEST C burning flake 

 

 

 

 OBSERVATION Sample C burst into honey. It burns with non coarse blue honey without soot. Tintless gas that turns wet blue acid test paper faint red and turns like water milky is present. 

 

 

 

 Conclusion C is changeable and flammable. The gas is CO2 from combustion of saturated organic conflation. 

 

 

 

 (2bi) 

 

 TEST C distilled water shake 

 

 

 

 OBSERVATION Clear or tintless result is observed 

 

 

 

 Conclusion C is miscible with water 

 

 

 

 (2bii) 

 

 TEST C Acidified K2Cr207 

 

 

 

 OBSERVATION Orange color of K2Cr207 result turns pale green and eventually pale blue on cooling 

 

 

 

 Conclusion C is a reducing agent 

 

 

 

 (2C) 

 

 TEST D C 10 NaOH Shake 

 

 

 

 OBSERVATION D dissolves slowly in C and produces sanguine brown result. Sanguine brown result turns pusillanimous precipitate. The precipitate has an antiseptic odour 

 

 Conclusion D is answerable in organic cleansers 

 

 

 

 (2d) 

 

 Conflation belongs to the class of secondary alkanol 

 

 ===================================== 

 

 (3ai) 

 

 Zinc nitrate 

 

 

 

 (3aii) 

 

 2 Zn (NO 3) 2 — –> 2 ZnO 4 NO 2 O 2 

 

 

 

 (3aiii) 

 

 It turns white when cold from it pusillanimous colour when it was hot 

 

 

 

 (3b) 

 

 Pipette/ measure50.0 cm3 of the stock affect into a 250 

 

 cm3 volumetric teacup ( containing some distilled water). Shake/ wind and add farther distilled water until the mark is reached. 

 

 

 

 (3c) 

 

 Al2 (SO4) 3 – turns blue acid test red 

 

 

 

 

 

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